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antiderivative of 1+cos^2(x) secx dx?
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whats cos x sec x = .. ?
that's my problem, I don't know how to rewrite that
isn't it simply 1?
its \(\int 1+ \cos^2 x \sec x dx\) right ?
yup
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yes so cos^2 x sec x is just cos x
oh ok
\( \int 1+\cos x dx\)
using def of secx right?
so antiderivative is sinx+x
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+C yes
thanks
welcome ^_^
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