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Help please? Once the rocket is launched, its height in feet, h(t), can be found using the height function h(t) = -16t² + 96t where t represents time in seconds. Find the time when the rocket finally hits the ground. My work: 0=-16t^2+96t = -16t(t-6)=0 = -16t=0 , t=0 and t-6= t=6
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yes thats correct t=0 corresponds to time fired t = 6 to the time it returns to ground
Thank you so much!
yw
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