Question

2x-3y+z=7
x+y+z=4
x+3=2x
solve for x, y, and z
I got x=23/7
y=73/7
z=22/7
not sure if it is correct

Answer 1

x+3=2x
3 = 2x - x
3 = x

x= 3

Answer 2

x+y+z=4
3+y+z = 4
y+z = 4-3
y+z = 1
y = 1-z

then

2x-3y+z=7
2(3) - 3(1-z) + z = 7
6 -3+3z+z = 7
3+4z = 7
4z = 7-3
4z = 4
z = 4/4
z =1

Answer 3

So

y = 1-z
y=1-1
y = 0

Answer 4

it must be x = 3, y=0, z=1

Answer 5

thanks

Answer 6

you are welcome @typhlosion

Answer 7

you are the best!

Answer 8

don't forget for medal :)