Question

(-2xy)^3/4xy^2

Answer 1

rewrite the numerator

\[\frac{-2^3x^3y^3}{4xy^2} = \frac{-8x^3y^3}{4xy^2}\]

so simplify the numbers 1st -8/4 =

then apply the index law for division, same base subtract the powers

\[\frac{x^a}{x^b} = x^{a - b}\]

hope it helps