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Mathematics 16 Online
OpenStudy (anonymous):

y1 -3/y^2 = 2/x^3 , solving for y1 so would it be y1=y^2/x^2 ?

OpenStudy (anonymous):

* -3y^2-2/x^2

OpenStudy (anonymous):

no wait sorry what I wrote first was fine. except its =2/x^2

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