Question

Solve for x: Arctan(1-x)-Arctanx=pi

Answer 1

\[\tan^{-1}(a) - \tan^{-1}(b) = \tan^{-1}({\frac{a - b}{1 + ab})}\]

Answer 2

wolfram says no solutions exist
http://www.wolframalpha.com/input/?i=Arctan%281-x%29-Arctanx%3Dpi

Answer 3

tan pi=0, so, 1-2x=0, so x=0.5

Answer 4

x= 1/2 should not be the solution.. :)

Answer 5

Put in back in the equation, \(0 \ne \pi\) ??

Answer 6

arctan((1-2x)/(1+x-x^2))=pi, so it should. Where isn't it satisfying again?