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find no of soln of(sin2x+cos2x)^(1+sin4x)=2
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looks like a log might start it off right
(sin2x+cos2x)^(1+sin4x)=2 (1+sin(4x)) log(sin(2x)+cos(2x)) = log(2) hmm, no ideas come to mind afterwards
maybe find some identintes to get it all into the same argument ... all of the form (kx) maybe
any thoughts?
I noticed something interesting here that may help:\[(\sin(2x)+\cos(2x))^2=\sin^2(2x)+\cos^2(2x)+2\sin(2x)\cos(2x)\]\[\text{ }=1+2\sin(2x)\cos(2x)=1+\sin(4x)\]
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