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OpenStudy (anonymous):
sin^2x = 1 _________________ sin^2x = 1 -1 -1 sin ^2x - 1 = 0 cos^2x = 0 square root of each above cosx = 0 x = pi/2 + 2pi n, 3pi/2 + 2pi n IS THIS RIGHT
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OpenStudy (anonymous):
precal help please
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