A picture frame has a perimeter of 40 inches. Its length is 2 inches greater than one-half its width. Let w represent the width of the picture frame, and let l represent the length. Which system of equations can be used to find the dimensions of the picture frame?

2l+2w=40
l=2+1/2w

2l+2w=40
l=1/2w-2

lw=40
l=1/2w-2

lw=40
l=2+1/2w

Question

A picture frame has a perimeter of 40 inches. Its length is 2 inches greater than one-half its width. Let w represent the width of the picture frame, and let l represent the length. Which system of equations can be used to find the dimensions of the picture frame?

2l+2w=40
l=2+1/2w

2l+2w=40
l=1/2w-2

lw=40
l=1/2w-2

lw=40
l=2+1/2w

tkhunny · Answer

Have you considered constructing your own system from the given information?

anonymous · Answer

no i dont even know where to start

tkhunny · Answer

I do not believe that.

There is one difficulty with the problem statement.  It doesn't tell us it's a rectangle.  If we assume that, we can proceed.

The length of the rectangle is "l".
The width of the rectangle is "w"

There, you're almost half done.  What's next?

anonymous · Answer

multiply the 2? i got the first one

tkhunny · Answer

You must translate the problem statement carefully.

" Its length is 2 inches greater than one-half its width"

l = w + 2

You translate the next statement.

anonymous · Answer

l=1/2w+2?