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Algebra
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write each quadratic function in vertex for. Find the coordinates of the vertex and the equation of the axis of symmetry. f(x) = -1/2x^2
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the axis of symmetry is \(\huge \frac{-b}{2a}\) where \(\large ax^2+bx+c\). Here b is 0 so we have an axis of symmetry of \(\huge \frac{-0}{2*\frac{-1}{2}}= \frac{0}{-1}\) or just 0 a look at the graph confirms this
similarly the vertex would be (0,0)
THANK YOU @bibby
np, yo
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