Question

A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle.

3 to the 2 over 3 power inches squared

3 to the 8 over 3 power inches squared

9 inches squared

9 to the 2 over 3 power inches squared

Answer 1

@iGreen

Answer 2

width = 3^(2/3)
length = cube root of 81 = 3

area = 3 * 3^(2/3)

use the rule of indices:- x^n * x^m = x^(n+m)

Answer 3

so it would be....

Answer 4

oops sorry 3 is not the cube root of 81 silly me!!!

Answer 5

i think it is isnt it?

Answer 6

no 81 = 3*3*3*3

3 is the 4th root of 81

Answer 7

so it would be 27

Answer 8

3 is cube root of 27 - yes

Answer 9

u sure you have the question right?

Answer 10

if you have have then
81 = 3^(4/3)

Answer 11

Cube root of 81 is the cube root of (27 * 3) which is 3 * 3^(1/3) now proceed.

Answer 12

or yes that too.

Answer 13

yes - as radar said

Answer 14

so its

3^(4/3) * 3^(2/3)

Answer 15

so the answer would beeeeeeeeeeeeee...............................

Answer 16

add 2/3 + 4/3

what do you get?

Answer 17

2

Answer 18

right

so its 3^2

Answer 19

3^2 = ?