A jet ski company charges a flat fee of $26.00 plus $3.25 per hour to rent a jet ski. Another company charges a fee of $24.00 plus $3.50 per hour to rent the same jet ski. Find the number of hours for which the costs are the same. Round your answer to the nearest whole hour.
a 2
b 8
c 10
d 12
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OpenStudy (love_to_love_you):
@iGreen
OpenStudy (love_to_love_you):
@TuringTest
OpenStudy (love_to_love_you):
@amistre64
OpenStudy (amistre64):
so each company charges a flat fee and a variable fee. you will want to develop some line equations to play with
OpenStudy (love_to_love_you):
how?
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OpenStudy (love_to_love_you):
@satellite73
OpenStudy (amistre64):
well, if we have to pay a flat fee, plus some fee based on an hourly rate .... how does this relate to a line equation?
OpenStudy (love_to_love_you):
26x+3.25y?
OpenStudy (amistre64):
i was thinking more of some y = mx + c variant :)
OpenStudy (amistre64):
costA = $26.00 + $3.25 per hour
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OpenStudy (love_to_love_you):
y=26+3.25x?
OpenStudy (amistre64):
costB = $24.00 plus $3.50 per hour
OpenStudy (amistre64):
yes
OpenStudy (love_to_love_you):
ok...
OpenStudy (amistre64):
and the solution is where the lines meet
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OpenStudy (love_to_love_you):
how do I find when the costs are the same?
OpenStudy (amistre64):
well, 2 lines cross where they have a pointin common
OpenStudy (amistre64):
costA = $26.00 + $3.25 per hour
costB = $24.00 + $3.50 per hour
when does A = B ?
$26.00 + $3.25 per hour = $24.00 + $3.50 per hour
solve for 'x'
OpenStudy (love_to_love_you):
where is x?
OpenStudy (amistre64):
x is a variable ... hour is variable
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OpenStudy (amistre64):
..read between the lines ... between ,,, the lions. ah weema wah ah wee mah wah
OpenStudy (love_to_love_you):
what in the world haha
OpenStudy (amistre64):
got side tracked lol
OpenStudy (amistre64):
26.00 + 3.25x = 24 + $3.50x
OpenStudy (love_to_love_you):
50=6.75x
7.4=x
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