Help ME PLEASE!!!!!!
Josiah is taking his friends to the movies. Each ticket costs $10, and popcorn is $5 a bag. There is a $3 service fee for the entire purchase. He has $75. If he buys 4 tickets, how many bags of popcorn can he buy?
If x = number of tickets and y = number of bags of popcorn, which of the following inequalities could you use to answer the problem?

Question

Help ME PLEASE!!!!!!
Josiah is taking his friends to the movies. Each ticket costs $10, and popcorn is $5 a bag. There is a $3 service fee for the entire purchase. He has $75. If he buys 4 tickets, how many bags of popcorn can he buy?
If x = number of tickets and y = number of bags of popcorn, which of the following inequalities could you use to answer the problem?

aum · Answer

Each ticket costs $10.  He bought "x" tickets.  Ticket cost = 10*x
Each bag of popcorn costs $5.  He bought "y" bags of popcorn.  Popcorn cost = 5*y
Service fee: $3
Total cost = 10x + 5y + 3 <=  $75   is the inequality.
10x + 5y <= 72
If x = 4, then 40 + 5y <= 72
5y <= 32
y <= 6.4
So y = 6 bags of popcorn.

aum · Answer

He can buy a maximum of 6 bags of popcorn.

anonymous · Answer

thank you