Question

Help ASAP?? I just need answers checked for Algebra 2
I fan and medal

Answer 1

1.What is the simplified form of (9x^2-25)/(3x+5)
I answered 3x+5 with a restriction of x =/ 5/3

2. What is the simplified form of (12z^2-7z-12)/(3z^2+2z-8)
I answered (4z+3)/(z+2)

3. What is the simplified form of {(x+3)/x^2-x-12}*{(x-4)/x^2-8x+6)}
I answered 1/(x-4)^2

Answer 2

1 incorrect this is difference of 2 squares
a^2 - b^2 = (a - b)( a + b)


correct is 3x - 5 x not = 5/3

Answer 3

2 you neeed to factor top and bottom

Answer 4

So would it be -5/3?

Answer 5

no x not = 5/3

Answer 6

- thats the restriction

Answer 7

oh okay sorry i got confused

Answer 8

1. answer is 3x - 5 with restriction x not = 5/3

Answer 9

okay, what about the other two?

Answer 10

12z^2-7z-12 - can you factor this?

Answer 11

= (4z + 3(3z - 4)

what about factors of 3z^2+2z-8 ?

Answer 12

= (3z )(z )

can you fill in the blanks?

Answer 13

you need to factor -8

Answer 14

Would it be (4z+3) (3z-4)

Answer 15

- thats the numerator - i did that in my above post what about the denominators factors?

Answer 16

Oops sorry I didn't see that post. And the denominator factors would be (3z-4) and (z+2)?

Answer 17

right

Answer 18

3z - 4 cancels out so your answer to 2 is correct

Answer 19

for 3 you need to factor the denominators and see if any factor will cancel

Answer 20

The factors for the first denominator are (x+3) and (x-4)

Answer 21

right - r u sure you've copied the other one correctly?

Answer 22

Oops, I messed up the second denominator, it is supposed to be x^2-8x+16

Answer 23

oh ok
what does that factor to?

Answer 24

(x-4)^2

Answer 25

right

Answer 26

3 is correct

Answer 27

Okay thank you. Could you help with a few more?

Answer 28

sorry gotta go

Answer 29

Okay that's fine. Thank you!

Answer 30

yw