Question

@freckles

Answer 1

Fun. A question without a calculator.

Answer 2

What's the derivative of arctan?

Answer 3

i got this, but i followed an example from my book and im not sure if it is right

Answer 4

looks like you found the derivative of arccos

Answer 5

\[\frac{ d }{ dx } \tan^{-1}x = \frac{ 1 }{ x^2+1 }\]

Answer 6

\[\frac{d}{dx}\arccos(x)=\frac{-1}{\sqrt{1-x^2}} \\ \frac{d}{dx}\arcsin(x)=\frac{1}{\sqrt{1-x^2}} \\ \frac{d}{dx}\arctan(x)=\frac{1}{1+x^2}\]

Answer 7

We only need that latter one or the one batman mentioned also

Answer 8

OHHH its

Answer 9

thank you i understand

Answer 10

Yup now it's right