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help pls? the area of a triangle whose altitude is 8 more than its base lenght x
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right angle triangle?
|dw:1413873542029:dw| \[area= \frac{ 1 }{ 2 } base \times hieght\] therefore, \[area= \frac{ 1 }{ 2 } (x) \times (x+8)\] \[area=\frac{ 1 }{ 2 }x ^{2} +4x\]
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