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Please HELP! If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1) = −3, g '(3) = 2, then find h '(1) if h(x) = the quotient of f of x and g of x.. 17 11 0 −11
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Per the quotient rule,\[h(x)=\frac{f(x)}{g(x)}~~\implies~~h'(x)=\frac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}\]
I got zero would that be the answer @SithsAndGiggles
Yes
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