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y = 1 ( x + 3 )^2 - 25
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So far i've got y=1x^2-16
1x+3^2-25
None.
1x+9-25
why wouldn't the ^2 apply to 1x?
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3x3=9
\((x+3)^2 = (x+3)(x+3) = x^2 + 3x + 3x + 3^2 = x^2+6x+9\)
u got rid of that wen multiply by 1
3x1=3
Do you ever know what you are doing? @kittycat123
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1timesx 1x or x
yes
Question is "y = 1 ( x + 3 )^2 - 25" Note "^2"
y=(x+8)(x-2)
where did you get 8..?
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When you simplify completely, then you factor it, you should get \((x+8)(x-2)\)
okay, thank you for all of your help !:)
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