Question

find b if v=<1/6,b) is a unit vector

Answer 1

\(\mathbf v = \langle\frac{1}{6},b\rangle\) ?

Answer 2

what?

Answer 3

\[\sqrt{(1/6)^2 + b^2)} =1\] how do i solve for b?

Answer 4

Try squaring both sides.