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Mathematics 22 Online
OpenStudy (anonymous):

how do you prove the following is equal? 1+cos2x/sin2x = cotx

OpenStudy (redheadangel):

TRIGONOMETRY FORMULAS TO BE USED. # 1+cos 2x= 2 cos^2x .....(1) # sin2x= 2sinx cosx ......(2) LHS (1+cos2x)/sin2x 2cos^2x/ 2sinx cosx .....[from (1) &(2)] cosx/sinx cotx=RHS

OpenStudy (anonymous):

1+cos^2(x)/sin^2(x) = cotx 1+cos^2(x)/sin^2(x) = cos x/sin x assume cosx/sinx = Y, then 1 + Y^2 = Y Y^2 - Y + 1 = 0 Solve Y

OpenStudy (anonymous):

use the quadratic formula

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