The distance D of an object thrown from height h (feet) at angle theta with velocity v is modeled by the formula
D = v^2sin theta cos theta = v cos theta sqrt((v sin theta)^2+64h)/32

Find D when h = 0 (that is when the object is projected from the ground

Question

The distance D of an object thrown from height h (feet) at angle theta with velocity v is modeled by the formula
D = v^2sin theta cos theta = v cos theta sqrt((v sin theta)^2+64h)/32

Find D when h = 0 (that is when the object is projected from the ground

anonymous · Answer

$$D=\frac{ v ^{2} \sin \theta \cos \theta+v \cos \theta \sqrt{(vsin \theta)^{2}+64h}}{32 }$$