A ball is thrown straight down from the top of a 304 ft building with an initial velocity of -12 feet per second. The position function is s(t)= -16t^2-12t+304. What is its velocity after 2 seconds? What is its velocity after falling 180 feet?

Question

anonymous · Answer

$$v _{0}=-12 fps$$g=-32fps

$$v=v _{0}-g*t$$

v=-12-(-32*2)
v=-76fps

Find the time at 180 feet

$$180=-16t ^{2}-12t+304$$$$0=-16t ^{2}-12t+124$$Solve for t using the quadratic equation.

Once you find t, use the velocity equation above using the new time.