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What is the probability of rolling a number greater than or equal to 9 with two dice, given that at least one of the dice must show a 6?
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8 ways to get 9 or more with those constraints 6-3,6-4,6-5,6-6,3-6,4-6,5-6,6-6 the probability will be successes/all possible. so 8 / all the possible rolls where 1 die is 6
A. 9/11 B. 4/11 C. 2/11 D. 7/11
It was 7/11 btw for any of you Apex people googling answers. :P
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