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OpenStudy (anonymous):
Please help!!! i give medals & fan!!! Algebra 2
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OpenStudy (anonymous):
Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function?
OpenStudy (anonymous):
4x + 8 2x + 12 x^2 - 4 x^2 - 16
OpenStudy (here_to_help15):
Those are denominators, and you can't divide by zero... so which one of those equals zero when x=2?
OpenStudy (anonymous):
x^2-4, right?
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