The sum of two numbers is 44. One number is 2 more than twice the other. Write a system of equations that defines this situation and solve using any method.

Question

anonymous · Answer

11+33

anonymous · Answer

the sum of two numbers ( we will use x and y)  sum means add
so, x + y = 44
one number is 2 more than twice the other , twice being *2
so x = 2y +2  (twice y, and 2 more)
substitute that for x in the first equation
(2y +2) + y = 44
simplify it,
2y +y =42 ... 3y = 42
divide out by 3.    y = 14
put that into the first equation
x + 14 = 44 .. solve for x ..x = 30
check if true , 30+ 14 = 44, true
2*14 +2 = 30, true
so numbers would be 14, and 30