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In how many ways can a teacher arrange 6 CDs in a collection of 12 CDs? A. 95,040 B. 11,880 C. 665,280 D. 1,320
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Say you have six slots: A through F you have 12 choices for slot A 11 for slot B etc etc all the way down to 7 choices for slot F Multiply those choices out: 12*11*10*9*8*7 = 665,280 this is effectively the same as computing the permutation P(12,6)
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