Question

a triangle has an area of 24 sq.m. the base 2 m longer than the height. what is the length of the base of the triangle?

Answer 1

Base= 8 m

Answer 2

\[A=24\]

\[A=\frac{ 1 }{ 2 }(B)(H)\] ( where B= H+2)

\[24=\frac{ 1 }{ 2}( h+2)(h)\]

\[48 = h^2+2h\]
\[h^2+2h-49=0\]

\[(h+8)(h-6)=0\]

H= -8 , 6 ( -8 is not possible)

Solving for B

B= h+2
= 6+2
=8

Answer 3

thnx