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Mathematics 16 Online
OpenStudy (anonymous):

Question related to speed-time graph and acceleration. in the attachments (circled one)

OpenStudy (anonymous):

OpenStudy (perl):

any luck ?

OpenStudy (anonymous):

Nope :/ i cant even understand the question

OpenStudy (anonymous):

and how to draw the graph

OpenStudy (dan815):

Okay

OpenStudy (dan815):

Acceleration=V/T

OpenStudy (dan815):

hello?

OpenStudy (anonymous):

yeah

OpenStudy (dan815):

okay if u are drawing a velocity per time graph

OpenStudy (dan815):

the slope of the line will be the acceleration because The slope of the line of a velocity time graph = Change in Y/Change in X which is Change in Velocity/ Change in Time

OpenStudy (anonymous):

mhm..

OpenStudy (dan815):

ok so draw it now

OpenStudy (dan815):

does it make sense?

OpenStudy (dan815):

and distance=v*t

OpenStudy (dan815):

so it should be the area under the graph

OpenStudy (dan815):

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