Question

Find two functions defined implicitly by the given relation:
x^2+y^2=36

Answer 1

\[
x^2+y^2=36 \\
y^2 = 36 - x^2 \\
y = \pm \sqrt{36-x^2} \\
y = +\sqrt{36-x^2} ~~\text{ and }~~y = -\sqrt{36-x^2}
\]

Answer 2

Correct @aum