The temperature at noon was –6.5⁰C. The temperature rose 3.5⁰C from noon to 1 p.m. The temperature decreased t degrees centigrade from 1 p.m. to 2 p.m. The temperature at 2 p.m. was –12⁰C.
Which equation can be used to solve for t?
A.
–6.5 – 3.5 – t = –12
B.
–6.5 + 3.5 + t = –12
C.
–6.5 + 3.5 – t = –12
D.
–6.5 – 3.5 + t = –12
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OpenStudy (anonymous):
@Here_to_Help15
OpenStudy (anonymous):
my last one
OpenStudy (here_to_help15):
Ok so here we add
OpenStudy (here_to_help15):
add 3.5 to -65
OpenStudy (here_to_help15):
-6.5 i meant
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OpenStudy (here_to_help15):
wait i thought nvm ok so new plan
OpenStudy (anonymous):
10.0
OpenStudy (here_to_help15):
thought you were suppose to solve hehehe
OpenStudy (anonymous):
o
OpenStudy (here_to_help15):
wait same thing haha so you add
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OpenStudy (anonymous):
lol
OpenStudy (here_to_help15):
its C
OpenStudy (anonymous):
one more please
OpenStudy (anonymous):
Point V is graphed on a number line at –6. Point U is 8 units away from point V on the number line.
What could be the coordinates of point U?
Choose all answers that are correct.
A.
–14
B.
–2
C.
1
D.
2