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Mathematics 17 Online
OpenStudy (anonymous):

help with this please :)

OpenStudy (anonymous):

OpenStudy (anonymous):

opps i got it i think its y=4x+9

Miracrown (miracrown):

First we get the slope of the tangent then that allows us to find the slope of the normal (it is the negative reciprocal of the slope of the tangent)

Miracrown (miracrown):

tangent slope is 4 so normal slope is -1/4

OpenStudy (anonymous):

ohhh

OpenStudy (anonymous):

y=-1/4(x-2) ?

Miracrown (miracrown):

y --1 not y

OpenStudy (anonymous):

sorry?

Miracrown (miracrown):

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