Question

MEDALS WILL BE GIVEN!!! Use the net to find the surface area of the rectangular prism. With the measurements of 6ft,11ft,6ft,11ft & height of 8ft.

Answer 1

Find the volume and surface area of the
given solids:
1).
Cube -
l = 2 in, w =2 in, and h = 2 in
V = 8 cubic inches
SA = 24 square inches

2).
Cube -
l =1 in, w = 1 in, and h = 1 in
V = 1 cubic inch
SA = 6 square inches

3).
Prism -
l = 7 in, w = 4 in, and h = 11 in
V = 308 in^3
Surface Area of Prism:
[ 2(lw) + (2l + 2w)h ]
= 56 + 22*11
= 298 square inches

4).
Rectangular prism -
l = 5 in, w = 4 in, and h = 3 in
V = 60 in^3
SA (Cuboid):
[ 2(lw) + (2l + 2w)h ]
= 40 + 18*3
= 94 square inches

5).
Pyramid
Volume =1/3 x area of base x height
Surface Area of Any Pyramid
= area of base + area of each of the lateral faces
Regular pyramid = area of base + 1/2 ps
where p = perimeter of the base, s = slant height
Square pyramid = b^2 + 2bs
where b = length of the base, s = slant height
Square pyramid -
l = 8 in, w = 8 in, and h = 10 in
s = sqrt (164)
V = 213 1/3 in^3
SA
= 64 + 16*(164)^(1/2)
= 268.89997559785115 in^2

Answer 2

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