Question

From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. If the base of the cliff is 205 feet from the boat, how high is the cliff (to the nearest foot)?

Answer 1

What do I have to do ? Because I am really confused , do I need to use tan?

Answer 2

yeah tan

Answer 3

can u do that

Answer 4

do i do tan of 26?

Answer 5

I dont understand the 26 1 part , I know the degree of that angle is 26 but what about the 1 , what does that mean

Answer 6

that is 26 degree 1 minute

Answer 7

So , how do I set up the equation , tan(26) ?

Answer 8

convert minute to degree

Answer 9

how do I do that

Answer 10

is it 1/60

Answer 11

yeah 1 minute =0.016 degree

Answer 12

so u have 26.016 degree put it

Answer 13

so it will be tan(26.016)

Answer 14

yeah

Answer 15

tan=perpendicular/ base

Answer 16

but do I have to do anything with the other information?

Answer 17

the base is 295

Answer 18

205 given in Q ..i type 295 by mistke ....distance of boat from cliff

Answer 19

oh yeah ok sorry 205 , ok so how do I set it up so I can get tan using that and the degree

Answer 20

is it 103 ft?

Answer 21

or 113

Answer 22

tan ()=perpendicular/205

Answer 23

perpendicular=205*tan

Answer 24

can u do that??

Answer 25

but what is the perpendicular ? there is no information on the length of the perp.

Answer 26

tan=0.488

Answer 27

that we are finding loll ..perpendicular = height of cliff

Answer 28

wait so its 0.488 times 205 which gives you 100 ft which is the perpendicular

Answer 29

yeah..that is 100.05 feet= height of cliff

Answer 30

oh ! now I get it , wow , thank you so much , great help !!

Answer 31

welcome :)