Question

y varies jointly with x and square of n. When y=25, x=3 and x=4. Find the value of y when x=5 and n=10

Answer 1

y=a*x*n^2
a= constant
25=a*3*4^2
25=a*3*16
25=a*48 find a

Answer 2

put in
y=a*x*n^2