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If f(x)=6x-2 and g(x)=x^4, what is (g ° f)(1)?
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(6x-2)^4
x^4(6x-2)
What is g of f
wait, that's a composition ?
i think one of us has mixed it up...
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i was just breaking it down without the 1 to show the steps
wait isn't it 16
g of f is g(f(x)) g(6x-2) (6x-2)^4 then replace x by 1
yes right tight sorry
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