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2log(x)-3log(x)+log(2x), rewrite as single logarithium
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a*log(b)=log(b^a)
log(x^2)-log(x^3)+log(2x)
log (a)-log(b)=log(a/b)
log(x^2/x^3)+log(2x)
log(1/x)+log(2x)
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log a + log b = log ab
apply this
@morganheist
Thank you so much! I just did it and it helped so much! Thanks!!
welcome :)
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