Question

OK who can help me with this problem ill post the link

Answer 1

you have to solve for a

Answer 2

multiply through by the denominator a-6b

this will give you 3 terms with "a" as a mutliple. Get these all on one side alone. Now factor the a out to get a(loads of crap) = other crap

divide by loads of crap to get a

Answer 3

ok thanks

Answer 4

what happens to be the answer though i just want to make sure i get the right answer

Answer 5

Isolate for a.

(a + 6b)/(a-6b) = -4k -5

Multiply both sides by (a-6b):

a+6b =-5*a + 30*b - 4a*k + 24b*k

Bring all the a's to one sides and the other variable to the other side

- add 5a to both sides
- add 4ak to both sides
- subtract 6b from both sides

a + 5a + 4ak = 30b + 24bk - 6b

Now take the common factor, a, out of the left side:

a( 1 + 5 + 4k) = 30b + 24bk -6b

Simplify:

a(4k + 6) = 24b + 24bk

Divide both sides by (4k + 6):

a = (24b + 24bk) / (4k + 6)

Simplify:

a = 24b( k + 1) / (4k + 6)

Answer 6

thanks so much that makes so much sense