Question

Find the derivative of the function of y=(2x+1)/(2x-1).

Answer 1

quotient rule for this one
\[\left(\frac{f}{g}\right)'=\frac{gf'-fg'}{g^2}\]
with
\[f(x)=2x+1,f'(x)=2,g(x)=2x-1, g'(x)=2\]

Answer 2

So \[\frac{ (2x-1)(2)-(2x+1)(2) }{ (2x-1)^2 }\]
which simplified is \[\frac{ (4x-2)-4x-2 }{ (2x-2)^2 }\]
and then \[\frac{ -4 }{ (2x-1)^2 }\]