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Suppose that f has an inverse and f(−4)=3, f′(−4)=4/7. If g=(1)/(f−1), what is g′(3)
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what does 1f-1 mean?
i wonder if you just mean that g is the inverse of f ?
\[\text{ if so } g'(3)=\frac{1}{f'(g(3))}\]
and if f(-4)=3 then g(3)=-4
if f and g are inverses
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g=(1)/(f−1)
\[g(x)=\frac{1}{f(x)-1}?\]
Use quotient rule
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