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(x^2-5)/(3x^3-7x) Is this symmetric about the origin?
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\[\large y = \dfrac{x^2-5}{3x^3-7x}\] like this ?
Yes
one way to check is by replacing x and y with -x and -y and see if you get the same equation
** it is symmetric about the origin if both the points (x, y) and (-x, -y) exist on the graph of the function
In different words y=f(x) is symmetric about the origin if f(-x)=-f(x)
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