Question

x^3-8 / x^2 -4

Answer 1

Subtract the powers, because that's what you gotta do when you divide! Also remember to divide -8 by -4. So, what will your answer be?

Answer 2

x+2

Answer 3

Yep, well done ^^

Answer 4

factor the numerator and denominator

\[\frac{(x^3 - 8)}{(x^2 - 4)}= \frac{(x -2)(x^2 + 2x + 4)}{(x -2)(x + 2)}\]

now cancel the common factor

Answer 5

would it be (x^2 +2x+4) / (x+2) ?

Answer 6

that's correct

Answer 7

Thank You!!