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Trigonometry 10 Online
OpenStudy (anonymous):

(Tanx-cotx)÷(tanx+cotx)=2sin^2x

OpenStudy (anonymous):

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OpenStudy (anonymous):

Is this an identity question?

OpenStudy (adamaero):

sin2x = 2sinxcosx if that helps

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Is 2sin^2x \[\Large 2\sin^2x\] that?

OpenStudy (anonymous):

@krista.breslin

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

So far I've got [(Sinx/cosx)-(cosx/sinx)]/[(Sinx/cosx)+(cosx/sinx)]

OpenStudy (anonymous):

@doulikepiecauseidont

OpenStudy (anonymous):

I couldn't get any farther than sin^2-cos^2

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