Question

MEDAL + FAN! :D

3y^2-6y+x+5=0
How to set it to vertex form?

Answer 1

pls :'(

Answer 2

pllllllllllllllllllllllllllllllllllllllllllssssssssssssssssssssssssssssssssssss

Answer 3

first take 3 out as follows
3(y^2 - 2y) + x +5 = 0
3[(y - 1)^2 - 1)] + x + 5 = 0
3(y -1)^2 - 3 + x + 5 = 0
3(y - 1)^2 + x + 2 = 0

Answer 4

Sorry for the late response and thanks.