Please Help! The container that holds the water for the football team is 1/2 full. After pouring in 3 gallons of water, it is 7/10 full. How many gallons can the container hold?
Let x = capacity of container (in gallons)
it's currently 1/2 full, so we have (1/2)*x gallons of water in it right now
you pour in 3 more gallons, so you add 3 to (1/2)*x to get (1/2)*x+3 the current gallon amount is now at (1/2)*x+3
at this amount, the container is 7/10 full, so (1/2)*x+3 is equal to (7/10)*x
the equation you need to solve is (1/2)*x+3 = (7/10)*x I'll let you do this
Thanks
np
But, i cant figure it out still, how do i solve this?
multiply both sides by the LCD 10 to clear out the fractions
that should help things a bit
what do you get when you do that?
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