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In a study of wait times at an amusement park, the most popular roller coaster has a mean wait time of 17.4 minutes with a standard deviation of 5.2 minutes. If 30 days are randomly selected, find the probability that the mean wait time is greater than 20 minutes. 0.0031 0.3207 0.1023 0.9987
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we can use TI 83/84 normalcdf ( 20, 1E99, 17.4, 5.2/sqrt(30))
this is actually a mean of a sample , so we have to change the standard deviation, divide by the square root of the sample size . (this is also called standard error )
= .003085... ~ .0031
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