OpenStudy (anonymous):

@shinalcantara @Secret-Ninja

OpenStudy (secret-ninja):

Wow... sorry. I have no idea how to solve this! :/

OpenStudy (shinalcantara):

$[2^8(5^{-5})(19^0)(\frac{ 5^{-2} }{ 2^3 })^4(2^{28}))$ 25 is the answer. the solution will follow haha

OpenStudy (chosenmatt):

25

OpenStudy (shinalcantara):

$[2^8(5^{-5})(19^0)]^{-2}$ let's start with this. remember that any number raise to zero is 1 and numbers with negative exponents can be expressed as its reciprocal with positive exponent $2^8 = 2^8$ $5^{-5} = \frac{ 1 }{ 5^5 }$ $19^0 = 1$ $[2^8(\frac{ 1 }{ 5^5 })(1)]^{-2} = \frac{ 5^{10} }{ 2^{16} }$ $[\frac{ 5^{-2} }{ 2^3 }]^4 = \frac{ 1 }{ 5^8(2^{12}) }$ $[2^8(5^{-5})(19^0)]^{-2} (\frac{ 5^{-2} }{ 2^3 })^4(2^{28})$ substituting the simplified values: $(\frac{ 5^{10} }{ 2^{16} })(\frac{ 1 }{ 5^8(2^{12}) })(2^{28})$

OpenStudy (shinalcantara):

2^16 * 2^12 = 2^28.. it will just cancel out you'll be left with 5^10/5^8 and that would be 5^2 = 25

OpenStudy (shinalcantara):

*and please don't bro me i'm a female o.o