@shinalcantara @Secret-Ninja

Question

secret-ninja · Answer

Wow... sorry. I have no idea how to solve this! :/

shinalcantara · Answer

$$[2^8(5^{-5})(19^0)(\frac{ 5^{-2} }{ 2^3 })^4(2^{28}))$$
25 is the answer. the solution will follow haha

chosenmatt · Answer

25

shinalcantara · Answer

$$[2^8(5^{-5})(19^0)]^{-2}$$
let's start with this.
remember that any number raise to zero is 1
and numbers with negative exponents can be expressed as its reciprocal with positive exponent
$$2^8 = 2^8$$
$$5^{-5} = \frac{ 1 }{ 5^5 }$$
$$19^0 = 1$$
$$[2^8(\frac{ 1 }{ 5^5 })(1)]^{-2} = \frac{ 5^{10} }{ 2^{16} }$$
$$[\frac{ 5^{-2} }{ 2^3 }]^4 = \frac{ 1 }{ 5^8(2^{12}) }$$
$$[2^8(5^{-5})(19^0)]^{-2} (\frac{ 5^{-2} }{ 2^3 })^4(2^{28})$$
substituting the simplified values:
$$(\frac{ 5^{10} }{ 2^{16} })(\frac{ 1 }{ 5^8(2^{12}) })(2^{28})$$

shinalcantara · Answer

2^16 * 2^12  = 2^28.. it will just cancel out
you'll be left with 5^10/5^8 and that would be 5^2 = 25

shinalcantara · Answer

*and please don't bro me i'm a female o.o