Question

@shinalcantara @Secret-Ninja

Answer 1

Wow... sorry. I have no idea how to solve this! :/

Answer 2

\[[2^8(5^{-5})(19^0)(\frac{ 5^{-2} }{ 2^3 })^4(2^{28}))\]
25 is the answer. the solution will follow haha

Answer 3

25

Answer 4

\[[2^8(5^{-5})(19^0)]^{-2}\]
let's start with this.
remember that any number raise to zero is 1
and numbers with negative exponents can be expressed as its reciprocal with positive exponent
\[2^8 = 2^8\]
\[5^{-5} = \frac{ 1 }{ 5^5 }\]
\[19^0 = 1\]
\[[2^8(\frac{ 1 }{ 5^5 })(1)]^{-2} = \frac{ 5^{10} }{ 2^{16} }\]
\[[\frac{ 5^{-2} }{ 2^3 }]^4 = \frac{ 1 }{ 5^8(2^{12}) }\]
\[[2^8(5^{-5})(19^0)]^{-2} (\frac{ 5^{-2} }{ 2^3 })^4(2^{28})\]
substituting the simplified values:
\[(\frac{ 5^{10} }{ 2^{16} })(\frac{ 1 }{ 5^8(2^{12}) })(2^{28})\]

Answer 5

2^16 * 2^12 = 2^28.. it will just cancel out
you'll be left with 5^10/5^8 and that would be 5^2 = 25

Answer 6

*and please don't bro me i'm a female o.o