x^3+3x^2+25x+75 zeros:-5i, 5i
What is the remaining zero? I looked up how to do this and it said to try long division and I did that and got a remainder of 25. Now I'm confused on what to do next

Question

x^3+3x^2+25x+75 zeros:-5i, 5i
What is the remaining zero? I looked up how to do this and it said to try long division and I did that and got a remainder of 25. Now I'm confused on what to do next

anonymous · Answer

http://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions.faq.question.635874.html

anonymous · Answer

Where does the x-3 come from?

anonymous · Answer

Yeah I saw that after that I tried all these other ways. I feel so dumb lol but thank you

anonymous · Answer

YW

anonymous · Answer

Divide the polynomial by ( x+5i)(x-5i)= x^2+25 You find the ratio to be (x+3) so the other root is x =-3