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can any one help me with this one 3(2x-3)<15
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First you must distribute the left side of the equation. What will you have?
6x
and
You have to distribute it to the 2x and -3
3x this where I don't understand how it's done
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nd
would a visual picture help you?
ok so 6x and 5x yes
You multiply each value in the parenthesis..IE distribute the 3 to(2x-3)..Thus you would multiply 3 times 2x and 3 times -3.
I'll show the steps but I wont answer it you'll have to answer it for yourself.
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you get 3x and 5x =15x ok
i would not distribute nothing \[ 3(2x-3)<15 \] divide by 3 and start with \[2x-3<5\]
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