Question

If beaker A contains a 15% solution of Lemonade and beaker B contains a 20% solution of Lemonade, how much from each beaker shoud be usede to make 10 liters of a 16% solution of lemonade

Answer 1

So we know there are 10 liters of the mix solution which is 16%= 10(0.16)
Lets say beaker A has x liters and is 15%= 0.15x
And beaker B has 10-x liters and is 20% = (10-x)0.20

Beaker A + Beaker B= mix
So
0.15x + (10-x)0.20 = 10(0.16)
Now try to solve for x

Answer 2

ok I will

Answer 3

you can get rid of decimals if you multiply everything by 100

Answer 4

I got 20 for x

Answer 5

No.

Answer 6

0.15x + (10-x)0.20 = 10(0.16)
0.15x + 2 -0.2x= 1.6
-2. -2
--------------------------
0.15x -0.2x = -0.4
-0.05x = -0.4
------ ----
-0.05. -0.05

x=?

Answer 7

I don't know why but for some reason I thought 10 time .2 was 20 sorry

Answer 8

It's ok. Everyone makes mistakes