Derrick and Mark are brothers who live in the same house. Mark is home, and Derrick is 5 mi from home. Both boys begin riding their bikes at the same time. Derrick rides directly home at a constant rate of 15 mph, and Mark rides away from home at a constant rate of 18 mph. Let d represent distance from home, and let t represent time in hours. Which system models this situation?
situation when they will meat ??
distance travelled by both must be equal to 5 mile
distance= speed *time
so speed x"s time
derrick with 15mph travel in time =??
their combined speed is 33 mph
- assuming their are approaching each other directly
Those are the answer choices
derrick speed=15 time=t distance=speed * time
mark speed=18mph time=t distance=??
sum of distance travelled by both =5 mi
A. d = 5 − 15t d = 18t B. d = 15 − 5t d = 18t C. d = 5 + 15t d = 18t D. d = 5 − 15t d = 5 + 18t
The answer choices
@perl can you help
@gorv
for derrick
speed= 15 time=t distance=speed*time so distance =?? plug in the values and tell what u got??
38
i dont understand
how u got 38
distance= speed*time what is speed of derrick
15+18=33 so i added 5 heres the answer choices, A. d = 5 − 15t d = 18t B. d = 15 − 5t d = 18t C. d = 5 + 15t d = 18t D. d = 5 − 15t d = 5 + 18t
@iGreen
can you please just help me @gorv
I can help
derrick speed=??
ok @perl do you know this I have to go somewhere in a few and have 5 math questions plz help
@perl lol who stopped u
Derrick and Mark are brothers who live in the same house. Mark is home, and Derrick is 5 mi from home. Both boys begin riding their bikes at the same time. Derrick rides directly home at a constant rate of 15 mph, and Mark rides away from home at a constant rate of 18 mph. Let d represent distance from home, and let t represent time in hours.
Look guys i just need help
I can help
one sec
A. d = 5 − 15t d = 18t B. d = 15 − 5t d = 18t C. d = 5 + 15t d = 18t D. d = 5 − 15t d = 5 + 18t theres my choices for answers
i will draw the situation
Ok :D
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